Question

Write 3 more Arithmetic Progressions.

Answer 1

Let's construct Arithmetic progressions :

Consider first term to be taken as “a ” and common difference to be “d ”

Let a = 3 , d = 3

then,

a + d = 3 + 3 = 6

a + 2d = 3 + 2 ( 3 ) = 3 + 6 = 9

a + 3d = 3 + 3(3) = 12

a + 4d = 3 + 4(3) = 15

a + 5d = 18 .

$\boxed{ \textbf{Therefore, Arithmetic progression = 3 , 6 , 9 , 12 , 15 , 18,......... }}$

Let a = 5 , d = 1

a + d = 5 + 1 = 6

a + 2d = 5 + 2(1) = 7

a + 3d = 5 + 3 = 8

a + 4d = 9

$\boxed{ \textbf{Therefore, Arithmetic progression = 5,6,7,8,9 ,.........}}$

Let a = 256 , d = -6

a + d = 256 - 6 = 250

a + 2d = 256 - 2(6) = 244

a + 3d = 256-3(6) = 238

a + 4d = 232

a + 5d = 228

$\boxed{ \textbf{Therefore, Arithmetic progression = 256 , 250 , 244 , 238 , 232 , 228,.........}} \:$

Hope helped! ^^

Answer 2

❤❤Here is your answer ✌ ✌
$\huge\underline {\red {\bold {Answer}}}$

Let's construct Arithmetic progressions : 

Consider first term to be taken as “a ” and common difference to be “d ”

Let a = 3 , d = 3 

then, 

a + d = 3 + 3 = 6 

a + 2d = 3 + 2 ( 3 ) = 3 + 6 = 9 

a + 3d = 3 + 3(3) = 12 

a + 4d = 3 + 4(3) = 15 

a + 5d = 18
}Therefore, Arithmetic progression = 3 , 6 , 9 , 12 , 15 , 18,......... ​

Let a = 5 , d = 1 

a + d = 5 + 1 = 6 

a + 2d = 5 + 2(1) = 7 

a + 3d = 5 + 3 = 8 

a + 4d = 9 
}Therefore, Arithmetic progression = 5,6,7,8,9 ,..

Let a = 256 , d = -6 

a + d = 256 - 6 = 250 

a + 2d = 256 - 2(6) = 244 

a + 3d = 256-3(6) = 238 

a + 4d = 232 

a + 5d = 228

Therefore, Arithmetic progression = 256 , 250 , 244 , 238