write 3 rulers of vedic maths with 3 ex. of each
Answers
1).Ekadhikena purvena Square of numbers ending in five 15^2 shall answered end up in 25 with tensing answer as taking remaining digits other than 5 adding 1 to it and multiplying. 1+1=2. (1*2=2) 15^2=225. 195^2=(19*20)/25=38025
2).if the units place add up to 10 with remaining digits being same then too apply the same result. 23*27 here 3+7=10, remaining digit is 2. So, (2*3)/21=621 this uses the antyordasakepi rule. 33*38=(3*4)/24=1224
3).Yavadunamtavadunikrutyam vargamca yojayet 13^2=(13+3)/3^2=169. 13 is three more than ten. So 13+3 is 16 and 3^2 is 9. 113^2 =(113+13)/13^2=(126)/169 but the base 100 has two zeros so 1 of 169 has to be carried to 126 so 12769 is the square of 113.
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Step-by-step explanation:
Learn the basics vedic maths questions with the help of our given solved ... Step 3: 6*1 + 3* 5 + 2*4 + 2 (carried) = 31 (write 1, carry 3)