Write 3 terms of given A.P when the first term 'a' & common difference 'd' is given as d= -2, a=4.
What is A
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Answer:
4, 2, 0
Since a=4, d=-2
So, 2nd term = 4+(-2)
= 2
Similarly third term = 2+(-2)
= 0
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Answer:
Lets take the AP as (a-d), a, (a+d)
Then the AP will be
1. (a-d) = [4-(-2)] = 6
2. a = 4
3. (a+d) = [4+(-2)] = 2
Hence, the AP formed is 6, 4 and 2.
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