Question

write 3 terms of GP when a=81,r=-1/3​

Answer 1

Answer:

Step-by-step explanation:

The terms of GP are a, ar, ar², ar³, ar⁴ ......

First term, a = 81

2nd term = ar = 81* 1/3 = 27.

3rd term term = 81* (1/3) ²= 9

4th term = 81 * (1/3)³ = 3

So the GP is 81, 27, 9 , 3, 1 ....

Answer 2

EXPLANATION :

$\star \: \underline {\underline{ \sf{Given}}} :$

1st term of GP a=81

and common ratio r=-1/3

$\star \underline{ \underline{ \sf{Solution}}} :$

$\sf \: 3rd\: term\:= a \times {(r)}^{n-1}$\\

\sf \: 3rd \:term = 81 \times {-\frac{1}{3}^{3}[/tex]

$\sf \: 3rd\: term = 9 </p><p>[tex] \to { \boxed {\mathfrak{9}}}$

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HOPE THIS IS HELPFUL...