Question

write 36 as a product of its prime factors.
Write the factors in order, from smallest to largest.
This is a mathswatch question I need your help :3

Answer 1

36 = 2*2*3*3

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Answer 2

Given:

Number=36

To find:

The factors

Solution:

The required factors from smallest to largest are 1, 2, 3, 4, 6, 9, 12, 18, and 36.

We can obtain the factors by expressing 36 as their product.

The required prime factors of 36=9×4

=3×3×2×2

=$2^{2}$×$3^{2}$

Now, the other factors are 1, 3, 2, 4, 9, 6, 12, 18, 36

So, these factors arranged from smallest to largest are 1, 2, 3, 4, 6, 9, 12, 18, and 36.

Therefore, the required factors from smallest to largest are 1, 2, 3, 4, 6, 9, 12, 18, and 36.