write 3log-2log3 as a single logarithm
Answers
Answered by
3
you have missed a number after 3log_.
I think it should be 3log2.
3 log2 - 2 log3
= log 2³ - log 3² (a logb = log (b^a))
=log(2³/3²) (log a - log b = log(a/b)
=log(8/9)
I think it should be 3log2.
3 log2 - 2 log3
= log 2³ - log 3² (a logb = log (b^a))
=log(2³/3²) (log a - log b = log(a/b)
=log(8/9)
Answered by
1
It should be 3log 2
then, 3log 2-2log 3
= log 2^3-log 3^2
= log 8-log 9
=log8/9
then, 3log 2-2log 3
= log 2^3-log 3^2
= log 8-log 9
=log8/9
Similar questions