Question

write 4 arithmetic sequence with 100 as the sum of first 4 terms​

Answer 1

Answer:

22, 24, 26, 28. Because 22+24+26+28 = 100.

19, 23, 27, 31. Because 19+23+27+31 = 100.

16, 22, 28, 34. Because 16+22+28+34 = 100.

13, 21, 29, 37. Because 13+21+29+37 = 100.

Additional: The trick here is to get 2 numbers, whose mean is 25. Ex:- 21 and 29. Then find the difference between them. 29-21 = 8. Finally, subtract 8 from 21 and add 8 to 29 to get the sequence. 21-8 = 13 and 29+8 = 37. So the sequence is 13, 21, 29, 37.

Step-by-step explanation:

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Answer 2

ANSWER: 4 Arithmetic sequence with 100 as the sum of the first four terms would be.

1. 22, 24, 26,28
2. 19, 23,27,31
3. 16, 22, 28,34
4. 13, 21,29,37

GIVEN:

Sum of 4 terms of arithmetic mean = 4

TO FIND :

4 Arithmetic sequence.

SOLUTION:

We can simply solve the problem as under:

Let the first number be 'n'.

(1) WITH DIFFERENCE = 2

we get, n+n+2+n+4+n+6=100

4n+12=100

n=88/4

so, n=22

Therefore the first Arithmetic sequence is 22,24,26,28….

the first Arithmetic sequence is 22,24,26,28….2) WITH DIFFERENCE, D=4

we get, n+n+4+n+8+n+12=100

4n=100–24

4n=76

so, n=19

Therefore Second Arithmetic sequence is 19,23,27,31…

3)WITH DIFFERENCE D=6

we get, n+n+6+n+12+n+18=100

4n=100–36

4n=64

n=16

Therefore, the Third Arithmetic sequence is 16,22,28,34…

4)With Difference D=8

we get, n+n+8+n+16+n+24=100

4n=100–48

4n=52

n=13

Therefore the Fourth Arithmetic sequence is 13,21,29,37

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