Question

write 43 as a diffrence of squares of two consecutive natural numbers

Answer 1

Step-by-step explanation:

Let the two consecutive natural numbers be x,x+1

Difference of squares of two consecutive natural numbers=43

(x)^2-(x+1)^2=43

(x)^2-(x)^2+2x+(1)^2=43

2x+1=43

2x=43-1

2x=42

x=42/2

x=21

Therefore,the two consecutive natural numbers are :x=21

x+1=22

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