Math, asked by krishnasikhwal07, 4 days ago

write 47 number as the difference of the square of two consecutive natural number.




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Answers

Answered by shikha37jain
1

Answer:

n + (n+1) = 47

2n +1 = 47

2n = 47 - 1

n = 46/2

n = 23

therefore n+1 = 24

(23 and 24 are the consecutive answers)

Answered by 471460
2

Step-by-step explanation:

N+ n+1, =47

2n +1 =47

2n=47-1

N=46/2

N=23

N+1 =24

I thick it's 23 and 24

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