Math, asked by SAKINARAZVI786, 5 months ago

Write 5 different linear equation in two variables and find three solutions for each of them...???
Can't understand this question .... can anyone help me plzz​

Answers

Answered by Pallakavya
3

Step-by-step explanation:

ANSWER

(i) x+y=10

(a) for x=1

1+y=10

y=9

(b) for x=2

2+y=10

y=8

(c) for x=3

3+y=10

y=7

(ii) 2x+y=15

(a) for x=1

2×1+y=15

y=15−2=13

(b) for x=2

2×2+y=15

y=15−4=11

(c) for x=3

2×3+y=15

(iii) 2x−y=0

(a) for x=1

2×1−y=0

y=2

(b) for x=2

2×2−y=0

y=4

(c) for x=3

2×3−y=0

y=6

(iv) 2x−y=1

(a) for x=1

2×1−y=1

y=2−1=1

(b) for x=2

2×2−y=1

y=4−1=3

(c) for x=3

2×3−y=1

y=6−1=5

(v) 2x+3y=0

(a) for x=1

2×1+3y=0

y=−2/3

(b) for x=2

2×2+3y=0

y=−4/3

(c) for x=3

2×3+3y=0

y=−6/3=−2

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Answered by pranavipise64
2

Answer:

(i) x+y=10

(a) for x=1

1+y=10

y=9

(b) for x=2

2+y=10

y=8

(c) for x=3

3+y=10

y=7

(ii) 2x+y=15

(a) for x=1

2×1+y=15

y=15−2=13

(b) for x=2

2×2+y=15

y=15−4=11

(c) for x=3

2×3+y=15

(iii) 2x−y=0

(a) for x=1

2×1−y=0

y=2

(b) for x=2

2×2−y=0

y=4

(c) for x=3

2×3−y=0

y=6

(iv) 2x−y=1

(a) for x=1

2×1−y=1

y=2−1=1

(b) for x=2

2×2−y=1

y=4−1=3

(c) for x=3

2×3−y=1

y=6−1=5

(v) 2x+3y=0

(a) for x=1

2×1+3y=0

y=−2/3

(b) for x=2

2×2+3y=0

y=−4/3

(c) for x=3

2×3+3y=0

y=−6/3=−2

Step-by-step explanation:

hope it's clear.

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