write 5 different linear equation into variables and find 3 solution for each them
Answers
Answered by
5
Divide 184 into two parts such that one third of one part may exceed one seventh of the other part by 8. Study later. Solve for x: x=(2x−73x)−34x−27−3. Study later. Solve the inequation: 42x−3+8≥2+34x solve 5x−1+2x−2=3x+1. I had Rs. 37−(3x+5)≥9x−8(x−3) Solve: (11−3y)(1−9y)=(85).
Answered by
12
Hope it helps you to gain knowledge ❣️❣️❣️
Attachments:
Similar questions