write 5 odd two digit numbers which have 8 in their ten's place
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0,1,2,3,4 if repetition is not allowed at unit place
fill by three numbers 0,2 or 4 and tens place occupie other number
P=3×3=9ways
Q=odd number divisible by (3) then its sum is multiple of three
Case−I 0,1,2,3
Number of ways =3×3=9
Case−II 2,3,4
number of way=3×2=6
Total odd numbers are formed Q=9+6=15
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