Math, asked by sakshay33, 4 months ago

write 5different linear equations in 2variables and find 3solutions for each of them

Answers

Answered by priya2013
1

Answer:

) x+y=10

(a) for x=1

1+y=10

y=9

(b) for x=2

2+y=10

y=8

(c) for x=3

3+y=10

y=7

(ii) 2x+y=15

(a) for x=1

2×1+y=15

y=15−2=13

(b) for x=2

2×2+y=15

y=15−4=11

(c) for x=3

2×3+y=15

(iii) 2x−y=0

(a) for x=1

2×1−y=0

y=2

(b) for x=2

2×2−y=0

y=4

(c) for x=3

2×3−y=0

y=6

(iv) 2x−y=1

(a) for x=1

2×1−y=1

y=2−1=1

(b) for x=2

2×2−y=1

y=4−1=3

(c) for x=3

2×3−y=1

y=6−1=5

(v) 2x+3y=0

(a) for x=1

2×1+3y=0

y=−2/3

(b) for x=2  

2×2+3y=0

y=−4/3

(c) for x=3

2×3+3y=0

y=−6/3=−2


sakshay33: tqqqq soo much
Answered by sidheswar18
0

(i) x+y=10

(a) for x=1

1+y=10

y=9

(b) for x=2

2+y=10

y=8

(c) for x=3

3+y=10

y=7

(ii) 2x+y=15

(a) for x=1

2×1+y=15

y=15−2=13

(b) for x=2

2×2+y=15

y=15−4=11

(c) for x=3

2×3+y=15

(iii) 2x−y=0

(a) for x=1

2×1−y=0

y=2

(b) for x=2

2×2−y=0

y=4

(c) for x=3

2×3−y=0

y=6

(iv) 2x−y=1

(a) for x=1

2×1−y=1

y=2−1=1

(b) for x=2

2×2−y=1

y=4−1=3

(c) for x=3

2×3−y=1

y=6−1=5

(v) 2x+3y=0

(a) for x=1

2×1+3y=0

y=−2/3

(b) for x=2

2×2+3y=0

y=−4/3

(c) for x=3

2×3+3y=0

y=−6/3=−2

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