Math, asked by mahihussain422, 10 months ago

Write 600 as a product of its prime factors in index form

Answers

Answered by parthamk2006
8

2|600

2|300

2|150

2|75

5|15

5|3

2*2*2*5*5*3 = 600

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Answered by payalchatterje
0

Answer:

600 as a product of its prime factors in index form is  {2}^{3}  \times  {5}^{2}  \times 3

Step-by-step explanation:

Given number is 600.

Here we want to find 600 as a product of its prime factors in index form.

This is a problem of Power of indices.

First we are breaking 600 into prime numbers 600 = 2 \times 2 \times 2 \times 5 \times 3 \times 5

So,600 =  {2}^{3}  \times  {5}^{2}  \times 3

600 as a product of its prime factors in index form is  {2}^{3}  \times  {5}^{2}  \times 3

Here applied formula is x \times x \times x...... \times n \: times =  {x}^{n}

Some others formulas of power of indices are

{x}^{0}  = 1 \\  {x}^{1}  = x \\  {x}^{a}  \times  {x}^{b}  =  {x}^{a + b}  \\  \frac{ {x}^{a} }{ {x}^{b} }  =  {x}^{a - b} \\  {x}^{ {y}^{a} }   =  {x}^{ya}  \\  {x}^{ - 1}  =  \frac{1}{x}  \\  {x}^{a}  \times  {y}^{a}  =  {(xy)}^{a}

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