write 63 as a product of prime factors in ascending order
Answers
Heya,
3 | 63
3 | 21
7 | 77
1 | 1
∴ Prime Factors of 63 = 3 × 3 × 7
In ascending Order [Smaller–Bigger]
3 = 3 < 7
Hope it helps !
63 = 3 x 3 x 7 is 63 as a product of prime factors in ascending order
"Prime Factorization is finding prime numbers which when multiplied together results in the original number"
Prime number is a natural number which has only two factors one and number itself. (e.g. , 2 , 3 , 5 , 7 .... )
Factorize 63
63 = 3 x 21
21 = 3 x 7
=> 63 = 3 x 3 x 7
3 and 7 are prime numbers,
Arrange them in ascending order
63 as the product of prime factors in ascending order 63 = 3 x 3 x 7
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