Question

write 6th term of an ap when the 1st term is 4 and common difference is - 3​

Answer 1

Answer :-

• The 6ᵗʰ term of A.P. is -11.

Step-by-step explanation:

To Find :-

• The 6ᵗʰ term of an A.P.

Solution :

Given that,

• First term of A.P. = 4
• Common difference = -3

We know,

• tₙ = a + ( n - 1 ) d,

Where,

• ₙ = nth term

• d = common difference

• a = first term

Therefore,

⇒ tₙ = a + ( n - 1 ) d

⇒ t₆ = 4 + ( 6 - 1 ) -3

⇒ t₆ = 4 + ( 5 )*-3

⇒ t₆ = 4 + ( - 15 )

⇒ t₆ = - 11

Hence, The 6ᵗʰ term of A.P. is - 11.

Answer 2

${ \boxed{ \underline{ \mathsf{ \pink{required \: \: answer}}}}}$

★GIVEN:-

• An AP

• 1st Term = 4

• Common difference = -3

★ TO FIND:-

• 6th term

★FORMULA USED:-

• $\sf{t_n = a + (n-1) d }$

• ( + )( - ) = ( - )

★SOLUTION:-

彡 HERE:-

• a = First term

• d = common difference

• n = nth term

So, we have to find the 6th term of an AP:-

$⬤ \: \: \: \sf{ t_6 = 4 + ( 6-1) \times ( -3)}$

$⬤ \: \: \sf{t_6 = 4 + 5 \times (-3)}$

$⬤ \: \: \sf{ t_6 = 4 \: - 15 }$

$\: \: \: \: \: \: \: \: \: \: \: \: \huge\sf \blue{t_6 = - 11}$

So, the 6th term of AP is -11.