write 75 as difference of the square of two consecutive natural numbers
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Answer:
let the two natural consecutive numbers be :
(x) & (x+1)
So,
(x+1)^2 - (x)^2 = 75
(x^2 +1 +2x) - (x)^2 = 75
x^2 - 1 - 2x - (x^2) = 75
-1 - 2x = 75
-2x = 75+1
-2x = 76
x = -76/2
x = -38
Verification:
(x+1)^2 -(x)^2 = 75
(- 38+1)^2 - (38)^2 = 75
(- 37)^2 - (38)^2 = 75
(1369) - (1444) = 75
75 = 75
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