Question

write a balanced chemical equation for cupric sulphite decomposes to form cupric oxide and Sulphur dioxide​

Answer 1

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$\bold{\small{\color{orange}{Using\:laws\:of\:conservation\:of\:mass}}}$

The laws of conservation of mass states that the total number of atoms of different elements in reactants are equal to the total number of atoms in different elements in products during the chemical reaction.

$\bold{\small{\color{green}{Balanced\:Chemical\:Equation:}}}$

$CuSO_3(s) --^{heat}--> CuO(s) + SO_2(g)$

It is a decomposition reaction.

$\bold{\small{\color{green}{Now\:see\:how\:to\:balance:}}}$

a).Number of Copper atoms in left hand side is equal to the number of copper atoms in right hand side is 1.

b). Number of Sulphur atoms in left hand side is equal to the number of sulphur atoms in right hand side is 1.

c). Number of oxygen atoms in left hand side is equal to the number of oxygen atoms in right hand side is 3.