write a balanced chemical equation to represent and aqua sodium hydroxide solution that is added to a copper sulphate solution forms a bluish white precipitate of copper hydroxide
Answers
Answer :-
It is given that aqueous sodium hydroxide (NaOH) solution is added to copper sulphate solution (CuSO₄) , and forms a bluish white precipitate i.e. Copper Hydroxide [Cu(OH)₂] .
Another product, which is formed in this reaction is aqueous solution of Sodium Sulphate (Na₂SO₄) .
NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄
[skeletal equation]
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On observing the above equation carefully, we will understand that the equation will be balanced if we multiply "NaOH" on the reactant side with 2 .
2NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄
[balanced equation] .
The obtained balanced equation will be more informative if we add "symbols of physical states" of the reactants and the products. So, here we write it :-
2NaOH (aq) + CuSO₄ (aq) → Cu(OH)₂ (s) + Na₂SO₄ (aq)
Answer:
Question :-
Write a balenced chemical equation to represent an aquaseous sodium hydroxide solution that is added to a copper sulphate solution forms a bluish white precipitate of copper hydroxide .
Answer :-
Solution :-
In the question given that,
Aquaseous solution of hydroxide solution that is added to a copper sulphate solution forms a bluish white precipitate of copper hydroxide.
Here first write an skeletal equation according to the given question,
NaOH +CuSO4 - Cu (OH)2 +Na2SO4.
Now ,
Here first considering number of moles of each molecules on reactant side
Na - 1×2=2
OH - 1×2=2
Cu - 1
So4 - 1.
Now,
Considering number of moles of each molecules on product side .
Na - 2
So4 -1
Cu - 1
OH -2
Here,
We can notice that Na and OH as twice the number of moles on the reactant side as comparing to product side .
Here we should multiply 2 on Na and OH .
Then we will get the balenced chemical equation that is ,
2NaOH +CuSO4 - Cu (OH)2+Na2SO4.
Therefore,
This is the perfect answer to your question..