Question

write a balanced chemical equation to represent and aqua sodium hydroxide solution that is added to a copper sulphate solution forms a bluish white precipitate of copper hydroxide​


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Answer 1

Answer:

It is given that aqueous sodium hydroxide (NaOH) solution is added to copper sulphate solution (CuSO₄) , and forms a bluish white precipitate i.e. Copper Hydroxide [Cu(OH)₂] .

Another product, which is formed in this reaction is aqueous solution of Sodium Sulphate (Na₂SO₄) .

NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄

[skeletal equation]

______________________________

On observing the above equation carefully, we will understand that the equation will be balanced if we multiply "NaOH" on the reactant side with 2 .

2NaOH + CuSO₄ → Cu(OH)₂ + Na₂SO₄

[balanced equation] .

The obtained balanced equation will be more informative if we add "symbols of physical states" of the reactants and the products. So, here we write it :-

2NaOH (aq) + CuSO₄ (aq) → Cu(OH)₂ (s) + Na₂SO₄ (aq)

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Answer 2

Answer:

In the question given that,

Aquaseous solution of hydroxide solution that is added to a copper sulphate solution forms a bluish white precipitate of copper hydroxide.

Here first write an skeletal equation according to the given question,

NaOH +CuSO4 - Cu (OH)2 +Na2SO4.

Now ,

Here first considering number of moles of each molecules on reactant side

Na - 1×2=2

OH - 1×2=2

Cu - 1

So4 - 1.

Now,

Considering number of moles of each molecules on product side .

Na - 2

So4 -1

Cu - 1

OH -2

Here,

We can notice that Na and OH as twice the number of moles on the reactant side as comparing to product side .

Here we should multiply 2 on Na and OH .

Then we will get the balenced chemical equation that is ,

2NaOH +CuSO4 - Cu (OH)2+Na2SO4.

Therefore,

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Explanation:

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