Question

Write a balanced equation for the following chemical reactions.

i) Hydrogen + Chloride —-> Hydrogen chloride

ii) Barium chloride + Aluminium sulphate —-> Barium sulphate + Aluminium chloride

iii) Sodium + Water —-> Sodium hydroxide + Hydrogen
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Answer 1

$\huge{\underline{\underline{\sf{\pink{Answer:-}}}}}$

i) H2 + Cl2 → 2HCl

ii) 3BaCl2 + Al2(SO4)3 →3BaSO4 + 2AlCl3

iii) 2Na + 2H2O → 2NaOH + H2

Answer 2

$\bf{\underline{Answers}}$

(i) $\sf{Hydrogen + Chlorine \longrightarrow Hydrogen\:Chloride}$

Chemical symbols of the substances involved in the reaction:-

$\sf{Hydrogen - H_2}$

$\sf{Chlorine - Cl_2}$

$\sf{Hydrogen Chloride - HCl}$

$\sf{\underline{Balanced \:Chemical\: Equation:-}}$

$\sf{H_2 + Cl_2 \longrightarrow 2HCl}$

Verification:-

LHS,

No. of atoms of Cl = 2

No. of atoms in H = 2

RHS,

No. of atoms in Cl = 2

No. of atoms in H = 2

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(ii) $\sf{Barium\: Chloride + Aluminium\: Sulphate \longrightarrow Barium\:Sulphate + Aluminium \:Chloride}$

Chemical symbols of the substances involved in the reaction:-

$\sf{Barium\:Chloride = BaCl_2}$

$\sf{Aluminium\:Sulphate = Al_2(SO_4)_3}$

$\sf{Barium\:Sulphate = BaSO_4}$

$\sf{Aluminium\:Chloride = AlCl_3}$

$\sf{\underline{Balanced \:Chemical\: Equation:-}}$

$\sf{3BaCl_2 + Al_2(SO_4)_3 \longrightarrow 3BaSO_4 + 2AlCl_3}$

Verification:-

LHS,

No. of atoms of Al = 2

No. of atoms of Ba = 3

No. of atoms of Cl = 6

No. of atoms of S= 3

No. of atoms of O = 12

RHS,

No. of atoms of Al = 2

No. of atoms of Ba = 3

No. of atoms of Cl = 6

No. of atoms of S= 3

No. of atoms of O = 12

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(iii) $\sf{Sodium + Water \longrightarrow Sodium Hydroxide + Hydrogen}$

Chemical symbols of the substances involved in the reaction:-

$\sf{Sodium = Na}$

$\sf{Water = H_2O}$

$\sf{Hydrogen = H_2}$

$\sf{\underline{Balanced \:Chemical \:Equation:-}}$

$\sf{2Na + 2H_2O \longrightarrow 2NaOH + H_2}$

Verification:-

LHS,

No. of atoms of S = 2

No. of atoms of H = 4

No. of atoms of O = 2

RHS,

No. of atoms of S = 2

No. of atoms of H = 4

No. of atoms of O = 2

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