Question

write a c++ program accept 5 integer numbers and print in reverse order using an array​

Answer 1

$\tt{\#\ incl ude < iostream >}\\\tt{using\ namespace\ std;}\\\tt{int\ main()}\\\{\\\quad\tt{int\ a[5],\ i,\ temp;}\\\quad\tt{cout < < "Enter\ 5\ numbers:";}\\\quad\tt{for(i=0;\ i < 5;\ i++)}\\\quad\quad\quad\tt{cin > > a[i];}\\\quad\tt{for(i=0;\ i < 2;\ i++)}\\\quad\{\\\quad\quad\quad\tt{temp=a[i];}\\\quad\quad\quad\tt{a[i]=a[4-i];}\\\quad\quad\quad\tt{a[4-i]=temp;}\\\quad\}\\\quad\tt{cout < < "The\ numbers\ in\ reverse\ order\ are\backslash n";}\\\quad\tt{for(i=0;\ i<5;\ i++)}\\\quad\quad\quad\tt{cout < < a[i] < < "\backslash t";}\\\quad\tt{return\ 0;}\\\}$

Answer 2

Answer:

\begin{gathered}\tt{\#\ incl ude < iostream > }\\\tt{using\ namespace\ std;}\\\tt{int\ main()}\\\{\\\quad\tt{int\ a[5],\ i,\ temp;}\\\quad\tt{cout < < "Enter\ 5\ numbers:";}\\\quad\tt{for(i=0;\ i < 5;\ i++)}\\\quad\quad\quad\tt{cin > > a[i];}\\\quad\tt{for(i=0;\ i < 2;\ i++)}\\\quad\{\\\quad\quad\quad\tt{temp=a[i];}\\\quad\quad\quad\tt{a[i]=a[4-i];}\\\quad\quad\quad\tt{a[4-i]=temp;}\\\quad\}\\\quad\tt{cout < < "The\ numbers\ in\ reverse\ order\ are\backslash n";}\\\quad\tt{for(i=0;\ i < 5;\ i++)}\\\quad\quad\quad\tt{cout < < a[i] < < "\backslash t";}\\\quad\tt{return\ 0;}\\\}\end{gathered}

# include<iostream>

using namespace std;

int main()

{

int a[5], i, temp;

cout<<"Enter 5 numbers:";

for(i=0; i<5; i++)

cin>>a[i];

for(i=0; i<2; i++)

{

temp=a[i];

a[i]=a[4−i];

a[4−i]=temp;

}

cout<<"The numbers in reverse order are\n";

for(i=0; i<5; i++)

cout<<a[i]<<"\t";

return 0;

}

Explanation:

15 thank + follow = inbox