Write a C++ program that accept a number from the user and determine whether it is odd or even.
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Solution.
Here comes the approach for the problem.
#include <iostream>
using namespace std;
int main() {
int n;
cout<<"Enter a number: ";
cin>>n;
if (n%2==0)
cout<<"Number is even.";
else
cout<<"Number is odd.";
return 0;
}
Explanation.
- A number is said to be even if it is divisible by 2. Here, we have checked whether the number leaves remainder when divided by 2.
- If the number leaves any remainder, then the number is odd or else, its even!
See attachment for output.
Attachments:
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