write a C program to accept principal rate of interest and number of year. compute simple interest
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Answer:
include<stdio.h>
#include<conio.h>
#include<math.h>
void main()
{
float simpleInterest(int ,int , float);
float compoundInterest(int ,int , float);
int p,t;
float r,s,c;
clrscr();
printf("Enter P,T,R :\n");
scanf("%d%d%f",&p,&t,&r);
s=simpleInterest(p,t,r);
c=compoundInterest(p,t,r);
printf("Simple interest = %9.2f\n",s);
printf("Compound interest = %9.2f\n",c);
getch();
}
float simpleInterest(int p,int t , float r)
{
return((p*t*r)/100.0);
}
float compoundInterest(int p ,int t, float r)
{
return(p*pow((1+r/100),t)-p);
}
Sample Output:
Enter P, T, R:
1234
23
2
Simple Interest = 567.64
Compound Interest = 711.89
Hope This would help you.
Thank You :)
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