Question

Write a c++ program to add two distances in inch feet system using Structure

INPUT FORMAT:

Input 1: Inch1 and feet1

Input 2 : Inch2 and feet2

OUTPUT FORMAT:

Sum of Distance

SAMPLE INPUT:

23

4.7

22

7.5

SAMPLE OUTPUT:

44'-6.7"​

Answer 1

   Answer:

#include <iostream>

using namespace std;

struct Distance{

int feet;

float inch;

}

d1 , d2, sum;

int main()

{

cin >> d1.feet;

cin >> d1.inch;

cin >> d2.feet;

cin >> d2.inch;

sum.feet = d1.feet+d2.feet;

sum.inch = d1.inch+d2.inch;

if(sum.inch > 12)

{

++ sum.feet;

sum.inch -= 12;

}  

cout << sum.feet << "'"<<"-"<< sum.inch << '"';

return 0;

}

Explanation:

Answer 2

Answer:

Explanation:

#include <stdio.h>

struct Distance {

  int feet;

  float inch;

} d1, d2, result;

int main() {

  printf("Enter 1st distance\n");

  printf("Enter feet: ");

  scanf("%d", &d1.feet);

  printf("Enter inch: ");

  scanf("%f", &d1.inch);

  printf("\nEnter 2nd distance\n");

  printf("Enter feet: ");

  scanf("%d", &d2.feet);

  printf("Enter inch: ");

  scanf("%f", &d2.inch);

  result.feet = d1.feet + d2.feet;

  result.inch = d1.inch + d2.inch;

  // while inch is greater than 12, changing it to feet.

  while (result.inch < 12.0) {

     result.inch = result.inch - 12.0;

     ++result.feet;

  }

  printf("\nSum of distances = %d\'-%.1f\"", result.feet, result.inch);

  return 0;

}