Write a c++ program to display integer from 1 to 10 except 6 and 9
Answers
Answered by
3
#include <iostream>
using namespace std;
int main()
{
for (int i = 1; i <= 10; ++i)
{
if ( i == 6 || i == 9)
{
continue;
}
cout << i << "\t";
}
return 0;
}
using namespace std;
int main()
{
for (int i = 1; i <= 10; ++i)
{
if ( i == 6 || i == 9)
{
continue;
}
cout << i << "\t";
}
return 0;
}
Answered by
0
Concept:
If a specified condition becomes true, then the continue statement breaks one iteration (in the loop) and continues the next iteration.
Program:
Write a c++ program to display integers from 1 to 10 except 6 and 9.
Solution:
#include <iostream>
using namespace std;
int main()
{cout << "List of integers from 1 to 10 except 6 and 9: "<< "\n";
for (int num = 1; num <= 10; num++)
{if ( num == 6 || num == 9)
{continue;
}
cout << num << "\n";
}
return 0;
}
Output:
Attachments:
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