Question

Write a c program to display perfect number from 1 to 100

Answer 1

#include<stdio.h>

int main(){

int sum=0,p,i;

printf("\n Perfect numbers between 1 and 100 are: ");

for(i= 1; i<= 100; i++){

p=1;

while(p<=(i/2)){

if(i % p == 0)

sum=sum+p;

p++;

}

if(sum==i)

printf(" %d ",i);

sum=0;

}

return 0;

}

, a perfect number is a positive integer that is equal to the sum of its proper positive divisors, that is, the sum of its positive divisors excluding the number itself.

Answer 2

Answer:

#include <iostream>

using namespace std;

int main()  

{

 cout << "\n\n Find the perfect numbers between 1 and 100:\n";

 cout << "------------------------------------------------\n";

 int i = 1, u = 1, sum = 0;

 cout << "\n The perfect numbers between 1 to 100 are: \n";

 while (i <= 100)  

 {

   while (u <= 100)  

   {

     if (u < i)  

     {

       if (i % u == 0)

         sum = sum + u;

     }

     u++;

   }

   if (sum == i) {

     cout << i << "  " << "\n";

   }

   i++;

   u = 1;

   sum = 0;

 }

}

Explanation:

Compile and execute to check results