Question

Write a c++ program to evaluate the following expression


X1= (-b+[√b^2-4ac]) /2a
and 2nd is

X2= [-b+(-√b^2-4ac)]\2a

Answer 1

Answer:

The idea is to take the values of a,b,c and then calculate the root of individual x1 and x2 . take a condition that if the square part is greater than zero then it will show the answer other wise both the answers will be same

Explanation:

#include <iostream>

#include <cmath>

using namespace std;

int main() {

   float a, b, c, x1, x2, rootanswer;

   cout << "Enter the values of  a, b and c: ";

   cin >> a >> b >> c;

   rootanswer = b*b - 4*a*c;

   

   if (rootanswer > 0) {

       x1 = (-b + sqrt(rootanswer)) / (2*a);

       x2 = (-b - sqrt(rootanswer)) / (2*a);

       cout << "x1 = " << x1 << endl;

       cout << "x2 = " << x2 << endl;

   }

    else if (rootanswer == 0) {

       cout << "the aanswers of the all the roots are same " << endl;

       x1 = (-b + sqrt(rootanswer)) / (2*a);

       cout << "x1 = x2 =" << x1 << endl;

   }

  return 0;

}

Answer 2

C++ program to evaluate the expression given:

#include <math.h>

void main()

{

double a,b,c, discriminant, root1, root2, realPart, imaginaryPart;

cout<<"Enter coefficients a, b and c respectively: ";

cin>>a;

cin>>b;

cin>>c;

discriminant = b*b-4*a*c;

if (discriminant > 0)

{

root1 = (-b+sqrt(discriminant))/(2*a);

root2 = (-b-sqrt(discriminant))/(2*a);

cout<<"root1 =” <<root 1;

cout<<”root2 = ”<< root2;

}

return;

}