Question

Write a C++ program to find out the area of a rectangle whose length=6cm&breadth=12cm

Answer 1

Answer:

#include <iostream>

using namespace std;

   int main()

   {

    int width, lngth, area, peri;

 cout << "\n\n Find the Area and Perimeter of a Rectangle :\n";

 cout << "-------------------------------------------------\n";  

       cout<<" Input the length of the rectangle : ";

    cin>>lngth;

 cout<<" Input the width of the rectangle : ";

    cin>>width;

    area=(lngth*width);

 peri=2*(lngth+width);

       cout<<" The area of the rectangle is : "<< area << endl;

       cout<<" The perimeter of the rectangle is : "<< peri << endl;  

       cout << endl;

       return 0;

   }

Explanation:

Answer 2

C program :

Explanation:

#include <stdio.h>//Header file.

int main()//Main function definition.

{

   float length=6,breadth=12,area;//Variable declaration.

   area=length*breadth;//Expression to find the area.

   printf("%f cm square",area);//print the value of area.

   return 0;

}

Output :

• The above code will gives the result as "72".

Code Explanation:

• The above code is in C-language, which gives the area by the help of defined value which is defined in the question.
• The area is printed with the help of printf function.

Learn more :

• C-Language : https://brainly.in/question/610076