Question

Write a C++ program to find the LCM of two numbers

Answer 1

understand this example, you should have the knowledge of following C++ programming topics:

C++ if, if...else and Nested if...elseC++ while and do...while Loop

LCM of two integers a and b is the smallest positive integer that is divisible by both a and b.

Example 1: Find LCM

#include <iostream> using namespace std; int main() { int n1, n2, max; cout << "Enter two numbers: "; cin >> n1 >> n2; // maximum value between n1 and n2 is stored in max max = (n1 > n2) ? n1 : n2; do { if (max % n1 == 0 && max % n2 == 0) { cout << "LCM = " << max; break; } else ++max; } while (true); return 0; }

Output

Enter two numbers: 12 18 LCM = 36

In above program, user is asked to integer two integers n1 and n2 and largest of those two numbers is stored in max.

It is checked whether max is divisible by n1 and n2, if it's divisible by both numbers, max (which contains LCM) is printed and loop is terminated.

Answer 2

Answer:

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Explanation:

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