Question

Write a c program to find the nth term of the series. 1,1,2,3,4,9,8,27,16,81,32,243,....

Answer 1

#include<stdio.h>
#include<conio.h>
void main()
{
int n,f,i;
printf("enter any number");
scanf("%d",&n);
I=f
while(i<=f)
{
n=n+I;
I++;
}
printf("nth term of series =%d",n);
getch();
}

this will guide
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Answer 2

• The series consists of table of 2 and table of 3 placed at the alternate positions.
• Following is the code to find the nth term of the series:

#include<stdio.h>

#include<math.h>   //Math header file included

int arr[100];           //Globally declared array

int main()              //Main function starts here

{  arr[0]=1;  arr[1]=1;

int j=1,k=1;

int position, i;

scanf("%d",&postion);

if(position==0||position==1)      //Array position starts from 0

{  printf("1");  }

  for(i=2;i<=position;i++)

  { if(i%2!=0)

   arr[i]=pow(3,j++);           //Predefined Power function used for table of 3

    else

   arr[i]=pow(2,k++);          //Table of 2

   }    

printf("%d",arr[position]);

}