Question

write a c program to print armstrong number
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Answer 1

Answer: mark asa brainliest and follow mec plz

Explanation: int check_armstrong(int); int power(int, int);

int main () { int c, a, b;

printf("Input two integers\n"); scanf("%d%d", &a, &b);

for (c = a; c <= b; c++) if (check_armstrong(c) == 1) printf("%d\n", c);

return 0; }

int check_armstrong(int n) { long long sum = 0, t; ...

t = n;

while (t != 0) { digits++;

Answer 2

Answer:

import java.util.*;

class abc

int main()

{

int num, original, rem, sum = 0, n = 0 ;

printf("Enter a Number: ");

scanf("%d", &num);

original = num;

while (original != 0)

{

original /= 10;

++n;

}

original = num;

while (original != 0)

{

rem = original%10;

sum += pow(rem, n);

original /= 10;

}

if(sum == num)

printf("%d is an Armstrong number.", num);

else

printf("%d is not an Armstrong number.", num);

return 0;

}