Question

Write a c program to read n integers ranging from 1 to n that contain only one duplication and finding the repeated value and mixed in the array

Answer 1

#include<stdio.h>int main(){  int arr[50];  int *p;  int i,j,k,size,n;  printf("\nEnter size of the array: ");  scanf("%d",&n);  printf("\nEnter %d elements into the array: ",n);  for(i=0;i<n;i++)    scanf("%d",&arr[i]);  size=n;  p=arr;  for(i=0;i<size;i++){    for(j=0;j<size;j++){         if(i==j){             continue;         }         else if(*(p+i)==*(p+j)){             k=j;             size--;             while(k < size){                 *(p+k)=*(p+k+1);                 k++;              }              j=0;          }      }  }  printf("\nThe array after removing duplicates is: ");  for(i=0;i < size;i++){    printf(" %d",arr[i]);  }  return 0;}

Answer 2

#include <stdio.h>

main()
{
  int A[100];  int i, j, n;
     printf"size: ");
     scanf("%d", &n);
     printf("values :  ");
      for (i=0; i<n;i++) scanf("%d", &A[i] );
    
     for (i = 0; i < n ; i++)  {
        for (j = i+1; j < n ;j++) {
           if (A[i] == A[j]) printf("%d th data item = %d is repeated\n",i,A[i]);
           for ( ; j<n-1; j++)  A[j] = A[j+1] ;  // remove the repeated one.
           n --;
        }
    }
   printf("the data items are : ");
   for (i=0; i<n; i++)  printf("%d  ", A[i]);

}