write a c programme to create a linked list with a given structure
struct node{
int rollno;
char* name;
struct node* link};
add two nodes with given details and display the nodes.
Answers
Explanation:
struct node
{
int num; //Data of the node
struct node *nextptr; //Address of the next node
}*stnode;
void createNodeList(int n); // function to create the list
void displayList(); // function to display the list
int main()
{
int n;
printf("\n\n Linked List : To create and display Singly Linked List :\n");
printf("-------------------------------------------------------------\n");
printf(" Input the number of nodes : ");
scanf("%d", &n);
createNodeList(n);
printf("\n Data entered in the list : \n");
displayList();
return 0;
}
void createNodeList(int n)
{
struct node *fnNode, *tmp;
int num, i;
stnode = (struct node *)malloc(sizeof(struct node));
if(stnode == NULL) //check whether the fnnode is NULL and if so no memory allocation
{
printf(" Memory can not be allocated.");
}
else
{
// reads data for the node through keyboard
printf(" Input data for node 1 : ");
scanf("%d", &num);
stnode->num = num;
stnode->nextptr = NULL; // links the address field to NULL
tmp = stnode;
// Creating n nodes and adding to linked list
for(i=2; i<=n; i++)
{
fnNode = (struct node *)malloc(sizeof(struct node));
if(fnNode == NULL)
{
printf(" Memory can not be allocated.");
break;
}
else
{
printf(" Input data for node %d : ", i);
scanf(" %d", &num);
fnNode->num = num; // links the num field of fnNode with num
fnNode->nextptr = NULL; // links the address field of fnNode with NULL
tmp->nextptr = fnNode; // links previous node i.e. tmp to the fnNode
tmp = tmp->nextptr;
}
}
}
}
void displayList()
{
struct node *tmp;
if(stnode == NULL)
{
printf(" List is empty.");
}
else
{
tmp = stnode;
while(tmp != NULL)
{
printf(" Data = %d\n", tmp->num); // prints the data of current node
tmp = tmp->nextptr; // advances the position of current node
}
}
}