Write a complete C program that finds real roots of a quadratic equation
Answers
Answer:
Design (Algorithm)
Start.
Read a, b, c values.
Compute d = b2 4ac.
if d > 0 then. r1 = b+ sqrt (d)/(2*a) r2 = b sqrt(d)/(2*a)
Otherwise if d = 0 then. compute r1 = -b/2a, r2=-b/2a. print r1,r2 values.
Otherwise if d < 0 then print roots are imaginary.
Stop.
Explanation:
Answer:
# include<stdio.h>
# include<conio.h>
# include<math.h>
main (){
float a,b,c,r1,r2,d;
printf (“enter the values of a b c”);
scanf (“ %f %f %f”, &a, &b, &c);
d= b*b – 4*a*c;
if (d>0){
r1 = -b+sqrt (d) / (2*a);
r2 = -b-sqrt (d) / (2*a);
printf (“The real roots = %f %f”, r1, r2);
}
else if (d= =0){
r1 = -b/(2*a);
r2 = -b/(2*a);
printf (“roots are equal =%f %f”, r1, r2);
}
else
printf(“Roots are imaginary”);
getch ();
}