Question

Write a correct answer For Factorise.

Answer 1

Solution:

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Given:

To Factorize :

$\frac{2y^3}{72y} - \frac{2^3}{256}$

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Factorization:

$\frac{2y^3}{72y} - \frac{2^3}{256}$

=$\frac{y^2}{36} - \frac{8}{256}$

=$\frac{y^2}{36} - \frac{1}{32}$

=$(\frac{y}{6} )^2 - (\frac{1}{4 \sqrt{2} }) ^2$

we know that

a² - b² = (a + b)(a - b)

∴ $(\frac{y}{6} )^2 - (\frac{1}{4 \sqrt{2} }) ^2$

= $( \frac{y}{6} + \frac{1}{4 \sqrt{2} } )( \frac{y}{6} - \frac{1}{4 \sqrt{2}} )$

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                                           Hope it Helps !!