write a cubes of 5 natural no.s of which are multiple of 7 and verify the following. The cube of a multiple of 7 is a multiple of 7 cube
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Answer:
1) 14*14*14=2744,
2) 21*21*21=9261,
3) 28*28*28=21952,
4) 35*35*35=42875,
5) 42*42*42=74088.
Step-by-step explanation:
These are the 5 natural cube numbers which are multiples of 7 and are multiples of cube 7
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