Question

Write a degree of (x²+1) (x³+1)²​

Answer 1

Answer:

As,

(x2−1)2=(x3−1)2

Since,

(a−b)2=a2+b2−2ab

So, (x2−1)2=(x3−1)3

=(x2)2+12−2(x2)(1)=(x3)2+12−2(x3)(1)

=x4+1−2x2=x6+1−2x3

Taking x2 and x3 as Common in LHS and RHS respectively:-

=x2(x2−2)=x3(x2−2)

Cancelling (x2−2) on both sides :-

=x2=x3

As, there are only two numbers, 0 and 1 are the required solutions.

Alternate Method(The Beter Method) :-

Neglect the solution given above, the solution of solutions has arrived (Sarcasm) :-

(x2−1)2=(x3−1)2

=(x2−1)=(x3−1)2−−−−−−−√

=x2−1=x3−1

Cancelling 1 on both Sides :-

=x2=x3

Pretty much the same (^_^)

Hope it helps

Mark as BRAINLIST

Answer 2

Answer:

degree is 8

hope it HELPS you