Question

Write a diary entry on paying a visit to an old age home..




write Dairy entry :p



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Answer 1

$\huge\bf\underline\color{yellow} {\underline{Diary\: Entry}}$

Gandhi Nagar

10th jan ,2021

sunday, 9.30 p.m

Dear diary,

Today was an eventful day.For a long time I have been wanting to visit an old age home with my friends. We finally managed to make that plan work. The moment we entered there, we were greeted with a warm welcome. Everyone was happy seeing us. We introduced ourselves and gave them the fruits that we bought for them.The old age home has a full time nurse to take care of everyone. They also have a small cozy library and indoor board games to keep the old aged people engaged. I had a great time spending time with everyone.

Ishika

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Format of Diary entry:-

$\boxed{\begin{minipage}{6 cm}\\ \sf{Day/Date/Year }\\ \\ \sf{Time : 00:00 am / pm }\\\\\sf{Dear Diary ,}\\ \\ \\ \\ \sf{\dots \dots Body \dots \dots } \\ \\ \\ \\ \\ \sf{ABC}\end{minipage}}$

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be brainly ❤️~

Answer 2

Explanation:

Step-by-step explanation:

Given Equation:-

⠀⠀⠀⠀ $\sf{\bigg[ \dfrac{5 {x}^{2} - 10}{12 } \bigg] }$

To find:-

value of x

Solution:-

use factor theorem

take the value of equation =0

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \left [\dfrac {5x^2-10}{12}\right]=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow \dfrac {5x^2-10}{12}=0$

using cross multiplication

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2-10=0$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow 5x^2=10$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=\dfrac {10}{5}$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x^2=2$

$\\\qquad\quad\displaystyle\sf{:}\longrightarrow x=\sqrt {2}$

$\\\\\therefore\sf x=\sqrt {2}.$