write a divisibility rule of 1 2 3 4 5 6 7 8 9 10 11 12
Answers
This shows you the divisibility tests for 2, 3, 5, 7, and 11, so you can tell if those numbers are factors of a given number or not without dividing. Divisibility Test for 2: The last digit is 0, 2, 4, 6, or 8. Divisibility Test for 3: The sum of the digits is divisible by 3.
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1.)
Every no. Is divisible by 1 as,(any no. ) /1=1
2.) A number is divisible by 2 if the last digit of the number is 0, 2, 4, 6, or 8.
3.) A number is divisible by 3 if the sum of the digits of the number is divisible by 3.
4.) A number is divisible by 4 if the last two digits of the number are divisible by 4.
5.) A number is divisible by 5 if the last digit of the number is 0 or 5.
6.) A number is divisible by 6 if the number is divisible by both 2 and 3.
7.) If you double the last digit and subtract it from the rest of the number and the answer is: 0 or divisible by 7.
Example: 672 (Double 2 is 4, 67-4=63, and 63/7=9)
8.) The last three digits are divisible by 8.
Example: 109816 (816/8=102)
9.) A number is divisible by 9 if the sum of the digits is divisible by 9.
10 .) A number is divisible by 10 if the last digit of the number is 0.
11.) If you sum every second digit and then subtract all other digits and the answer is: 0 or divisible by 11.Example: 1364 ((3+4) - (1+6) =0) & 3729 ((7+9) - (3+2) = 11
12.) The number is divisible by both 3 and 4 648 (By 3? 6+4+8=18 and 18/3=6
By 4? 48/4=12)