Question

write a for-loop that iterates over start_list and .append()s each number squared (x ** 2) to square_list. then sort square_list!

Answer 1

Héy!!!

So, thé answer is... ---start_list = [5, 3, 1, 2, 4] square_list = [] for number in start_list: # Your code here! start_list.append(number ** 2) square_list.sort() print square_list


#ThankYou

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@Ramsharma