Question

write a formula for y from x²/a² + y²/b² = 1. If a = 6,b = 4, and x = 3,find the positive value of y​

Answer 1

Hello, Buddy!!

||Required Solution||

→ x²/a²+y²/b² = 1

[tex][/tex]

• a = 6
• b = 4
• x = 3

→ (3)²/(6)²+y²/(4)² = 1

→ 9/36+y²/16 = 1

• LCM of 16 & 36 is 144

→ 36/144+9y²/144 = 1

→ 36+9y²/144 = 1

→ 36+9y² = 144

→ 9y² = 144-36

→ y² = 108/9

→ y² = 12

→ y = √12

→ y = 2√3

• Required Value of y ☞ 2√3

@MrMonarque♡

Hope It Helps You ✌️

Answer 2

Answer:

Hello, Buddy!!

||Required Solution||

→ x²/a²+y²/b² = 1

a = 6

b = 4

x = 3

→ (3)²/(6)²+y²/(4)² = 1

→ 9/36+y²/16 = 1

LCM of 16 & 36 is 144

→ 36/144+9y²/144 = 1

→ 36+9y²/144 = 1

→ 36+9y² = 144

→ 9y² = 144-36

→ y² = 108/9

→ y² = 12

→ y = √12

→ y = 2√3

Required Value of y ☞ 2√3

@MrMonarque♡

Hope It Helps You ✌️