Question

Write a fraction with numerator x and denominator y. If the numerator is increased by 6. the fraction becomes 1/2 If its denominator is increased by 7, the fraction becomes 1/3 Find the fraction.​

Answer 1

Answer:

⇢

$\frac{19}{50} \: is \: the \: required \: answer$

Step-by-step explanation:

Given :- Fraction is x/y

⇢ If numerator is increased by 6 fraction becomes 1/2 so

● eq. 1

$\frac{x + 6}{y} = \frac{1}{2}$

⇢ If denominator is increased by 7 fraction becomes 1/3 so

● eq. 2

$\frac{x}{y + 7} = \frac{1}{3}$

$By \: solving \: equation \: 1 \: we \: get \\ \\ 2(x + 6) = y \\ \\ 2x + 12 = y \\ \\ Assuming \: it \: as \: equation \: 3$

$By \: solving \: equation \: 1 \: we \: get \\ \\ 2(x + 6) = y \\ \\ 2x + 12 = y \\ \\ Assuming \: it \: as \: equation \: 3$

$By \: solving \: equation \: 2 \: we \: get \\ \\ 3x = y + 7 \\ \\ substituting \: value \: of \: y \: by \: \\ equation \: \\ 3$

$3x = 2x + 12 + 7 \\ 3x - 2x = 12 + 7 \\ x = 19 \\ \\ substituting \: x \: in \: equation \: 1$

$y = 2(19) + 12 \\ y = 38 + 12 \\ y = 50$

Hence required fraction is :-

$\frac{19}{50}$

Hope my answer helped you mate :)