Question

Write a function called Remove_keys (mydict, keylist) that accepts 3

two parameters: a dictionary called mydict and a list called keylist.

34

Remove _keys(mydict, keyist) should remove all the keys

contained in keylist from mydict and return dictionary:

d="key1": "value1", "key2" : "value2", "key3" : "value3", "key4"

:"value4

keys = l"key1", "key3", "key5"| if Remove_keys(d, keys) returns to a dictionary- "key2"value2", "key4": "valu​

Answer 1

$\texttt{\textsf{\large{\underline{Solution}:}}}$

The given co‎de is written in Python.

def Remove_keys(mydict,keylist):

   for i in keylist:

       mydict.pop(i,None)

   return mydict

The above fu‎nction takes a dictionary and list as parameter. Then, the keys present in both dictionary as well as in keylist are deleted from the dictionary using pop() fu‎nction.

We can check our result by an example,

def Remove_keys(mydict,keylist):

   for i in keylist:

       mydict.pop(i,None)

   return mydict

   

dictionary={1:'A', 2:'B',3:'C',4:'D',5:'E',6:'F'}

keylist=[1,2,4,5]

print("Original Dictionary:")

print(dictionary)

dictionary=Remove_keys(dictionary,keylist)

print("New Dictionary:")

print(dictionary)

Output:

Original Dictionary:

{1: 'A', 2: 'B', 3: 'C', 4: 'D', 5: 'E', 6: 'F'}

New Dictionary:

{3: 'C', 6: 'F'}

See the attachment for output.