Question

Write a function called stop_at_four that iterates through a list of numbers. Using a while loop, append each number to a new list until the number 4 appears. The function should return the new list.

>>>> def stop_at_four():
[PYTHON]

Answer 1

PSEUDOCODE

1 : Get the list of number

2 : Iterates through the list

3 : Append each number to a new list

4 : If number 4 appears, stop the loop and return the list

Code:

def stop_at_four(num_list):

new_list = []

counter = 0

while True:

if num_list[counter] == 4 and counter < len(num_list) - 1:

break

new_list.append(num_list[counter])

counter += 1

return new_list[:]

print(stop_at_four(input().split(' ')))

Example:-

Input: 1 5 7 3 4 7 8

Output: [1,5,7,3]

There are many complex approaches to this problem which requires comparatively lesser code than this but I want to make it simpler because Simple is better than complex.

Some Information :-

◉ While loop iterates as long as the condition remains true.

◉ We can return or use a copy of a list without making the list empty which generally occurs when we return the exact list from a function or block, by using the following syntax, list_name[:] , It is also called list-slicing.

◉ The python split function splits a string into a list by using the separator passed as the function's parameter.

Answer 2

Your required answer is in the attached Pic.