Write a function that has one integer argument and returns 0 if number is even else returns 1.
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hey mate ur ans
using namespace std; int main() { int n; cout << "Enter an integer: "; cin >> n; if ( n % 2 == 0) cout << n << " is even."; else cout << n << " is odd."; return 0; }
hope it helps
using namespace std; int main() { int n; cout << "Enter an integer: "; cin >> n; if ( n % 2 == 0) cout << n << " is even."; else cout << n << " is odd."; return 0; }
hope it helps
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