Write a function using python called fizz_buzz that takes a number.
1. If the number is divisible by 3, it should return “Fizz”.
2. If it is divisible by 5, it should return “Buzz”.
3. If it is divisible by both 3 and 5, it should return “FizzBuzz”.
4. Otherwise, it should return the same number.
Answers
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def fizzler(num):
if num % 3 != 0 and num % 5 != 0:
return num
if num % 3 == 0 and num % 5 == 0:
return "FizzBuzz"
if num % 3 == 0:
return "Fizz"
return "Buzz"
if __name__ == "__main__":
number = int(input("Enter a number: "))
print(fizzler(number))
Answered by
1
Answer:def fizz_buzz(num):
if num%3==0:
return"Fizz"
if num%5==0:
return"Buzz"
if num%3==0 and num%5==0:
return"FizzBuzz"
else:
return(num)
num=int(input("enter any num:"))
print(fizz_buzz(num))
Explanation:
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