write a Java expression for A^4 + B^3 - XY/3
Answers
Answer:
Math.pow(A, 4) + Math.pow(B, 3) - X * Y/3
Explanation:
We can break the following mathematical expression into 3 different parts:
- A⁴
- B³
i) A⁴:
This expression is read as 'A to the power 4'.
The answer lies there.
'power'.
This means that we have to use the math function 'pow()'.
We get
Math.pow(A, 4)
Generally, we write the base first, i.e., A, which is followed by the
exponent, i.e., 4.
ii) B³:
This expression is read as 'B to the power 3'.
The answer lies there.
'power'.
This means that we have to use the math function 'pow()'.
We get
Math.pow(B, 3)
Generally, we write the base first, i.e., B, which is followed by the
exponent, i.e., 3, which has been stated above.
iii) :
This expression is read as 'XY by 3'.
The answer lies there.
'by'.
This means that it is a fraction.
Hence, we have to use the '/' operator here, since fraction in Java are
represented as 'a/b'.
Applying this, we get
XY/3
It is still incomplete.
Here, we cannot write 'XY' because in Java, it is not read as 'X into Y'.
This would produce a logical error.
To make the logic perfect, we apply the '*' operator.
After applying this, we get
(X * Y)/3
Brackets are to be applied for the calculation would become incorrect
due to operator precedence.
Now, fix the signs between the the 3 expressions.
The final answer will be
Math.pow(A, 4) + Math.pow(B, 3) - X * Y/3