Question

Write a java program logic to print the numbers from 15 to 9 in a reverse order using while loop?​

Answer 1

import java.util.Scanner;

class ReverseNumberWhile

{

public static void main(String args[])

{

int num=0;

int reversenum =0;

System.out.println("Input your number and press enter: ");

//This statement will capture the user input

Scanner in = new Scanner(System.in);

//Captured input would be stored in number num

num = in.nextInt();

//While Loop: Logic to find out the reverse number

while( num != 0 )

{

reversenum = reversenum * 10;

reversenum = reversenum + num%10;

num = num/10;

}

System.out.println("Reverse of input number is: "+reversenum);

}

}

Output:

Input your number and press enter:

145689

Reverse of input number is: 986541

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Answer 2

Answer:

import java.util.Scanner;

class ReverseNumberWhile

{

public static void main(String args[])

{

int num=0;

int reversenum =0;

System.out.println("Input your number and press enter: ");

//This statement will capture the user input

Scanner in = new Scanner(System.in);

//Captured input would be stored in number num

num = in.nextInt();

//While Loop: Logic to find out the reverse number

while( num != 0 )

{

reversenum = reversenum * 10;

reversenum = reversenum + num%10;

num = num/10;

}

System.out.println("Reverse of input number is: "+reversenum);

}

}