Write a Java program to accept a number and check the number is even or not. Prints 1 if the number is even or 0 if the number is odd.
Answers
Answered by
8
Answer:
import java.util.Scanner;
class EveOddPrint{
public static void main (String ar []){
Scanner sc=new Scanner (System.in);
System.out.println("Enter a number");
int a=sc.nextInt();
if(a%2==0)
System.out.println("1");
else
System.out.println("0");
}
}
Logic:-
- Accept a number
- Check if it is even or odd
- if even, print 1
- else print 0
Answered by
3
You may use the following program::
import java.util.Scanner;
public class Brainly {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
int usin = sc.nextInt();
if (usin % 2 == 0) {
System.out.println("1");
}
else {
System.out.println("0");
}
}
}
Output???
Sample input :-- 2
Sample output :-- 1
Logic::
==> Takes input and stores it in variable named usin.
==> Checks whether it returns 0 as remainder after divided by 2. If yes, it prints "1" otherwise "0".
Hope It Helps You..♪
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